Given the head of a singly linked list, return the middle node of the linked list.
If there are two middle nodes, return the second middle node.
Example 1:
Input: head = [1,2,3,4,5]
Output: [3,4,5]
Explanation: The middle node of the list is node 3.
Example 2:
Input: head = [1,2,3,4,5,6]
Output: [4,5,6]
Explanation: Since the list has two middle nodes with values 3 and 4, we return the second one.
class Solution {
public:
ListNode* middleNode(ListNode* head) {
ListNode *slow = head, *fast = head;
while(fast && fast -> next)
{
slow = slow -> next;
fast = fast -> next -> next;
}
return slow;
}
};